A monkey climbs 20 feet at the beginning of each hour and rests for a while when he slips back 5 feet before he again starts climbing in the beginning of the next hour. If he begins his ascent at 8:00 AM, at what time will he first touch a flag at 110 feet from the ground?

Question

When the time is 8:30, the angle between the minute hand and the hour hand of a clock is:

Answer 1

A monkey ascends 20 feet hourly but descends 5 feet. Thus, his hourly advancement is:

20 − 5 = 15 feet per hour.

Let's determine when he first touches a flag at 110 feet.

In hour one, he climbs 20 feet, reaching 20 feet.
In hour two, he climbs 20 feet, regressing 5 feet; his net is 20 − 5 = 15 feet. He's now at 20 + 15 = 35 feet.
In hour three, he climbs 20 feet, regressing 5 feet, for a net of 15 feet. He's at 35 + 15 = 50 feet.
Following this, he reaches 95 feet at the seventh hour's end, after climbing: 6 × 15 = 90 feet. He's at 95 feet at 3:00 PM.

Initially in hour eight, the monkey ascends 20 feet and will touch 115 feet. As he only needs 15 feet to reach the flag at 110 feet, he touches the flag during the eighth hour. The time he reaches the flag is therefore 3:00 PM.

A monkey climbs 20 feet at the beginning of each hour and rests for a while when he slips back 5 feet before he again starts climbing in the beginning of the next hour. If he begins his ascent at 8:00 AM, at what time will he first touch a flag at 110 feet from the ground?

The Correct Option is B

Solution and Explanation

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