To determine how much the microscope should be moved to focus on the mark again after placing a slab of glass over it, we need to understand how light behaves when it passes through the glass.
When a slab of glass with refractive index \(n\) and thickness \(t\) is placed over an object, the apparent shift in the position of the object is given by:
\(d = t \left(1 - \frac{1}{n}\right)\)
Where:
Substituting the given values into the formula:
\(d = 3 \left(1 - \frac{1}{1.5}\right) = 3 \times \left(1 - \frac{2}{3}\right) = 3 \times \frac{1}{3} = 1 \, \text{cm}\)
This means the mark appears to be shifted upwards by 1 cm due to the glass slab.
Thus, the microscope should be moved 1 cm upward to focus on the mark again.
The correct answer is: 1 cm upward