Question

A metallic mineral weighs 44 g and displaces 11 mL of water when fully immersed. The density of the mineral is ......... g/cc. (In integer)

Hint:

To calculate the density, divide the mass (in grams) by the volume (in cubic centimeters or milliliters).

Answer 1

Correct Answer: 4

Step 1: The density rule.
Density is mass divided by volume, \[ \rho = \frac{m}{V}. \]

Step 2: Read the data.
The mineral has a mass of 44 g. It pushes aside 11 mL of water, which equals its volume.

Step 3: Match the volume units.
Since 1 mL is the same as 1 cubic centimetre, the volume is 11 cc.

Step 4: Divide.
So \[ \rho = \frac{44}{11} = 4\ \text{g/cc}. \]

Step 5: State the answer.
The density is 4 g per cc.
\[ \boxed{4} \]