Question:medium

A metal crystallizes in cubic lattice with edge length of \(4\ \text{\AA}\). The number of unit cells of this metal present in \(128\ \text{cm}^3\) volume is

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For a cubic crystal, \[ \boxed{ \text{Number of unit cells} = \frac{\text{Total volume}}{a^3} } \] where \(a\) is the edge length of the unit cell.
Updated On: Jul 18, 2026
  • \(2\times10^{24}\)
  • \(4\times10^{24}\)
  • \(8\times10^{24}\)
  • \(16\times10^{24}\)
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The Correct Option is A

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