Question:medium
A man runs at a speed of 4 m/s to overtake a standing bus. When he is 6 m behind the door at \( t = 0 \), the bus moves forward and continuous with a constant acceleration of 1.2 m/s². The man reaches the door in time t. Then,
A man runs at a speed of 4 m/s to overtake a standing bus. When he is 6 m behind the door at \( t = 0 \), the bus moves forward and continuous with a constant acceleration of 1.2 m/s². The man reaches the door in time t. Then,
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In relative motion problems, ensure you account for the motion of both objects and set their positions equal at the time of interest.
Updated On: Apr 2, 2026
- \( 4t = 6 - 0.6t^2 \)
- \( 4t = 1.2t^2 \)
- \( 4t = 1.2t + 4t^2 \)
- \( 4t = 6 + 4t^2 \)
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The Correct Option is A
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