Question:medium

A man crosses a 320 m wide river perpendicular to the current in 4 min. If in still water he can swim with a speed 5/3 times that of the current, then the speed of the current, in m/min is

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To cross river perpendicularly, swimmer must head upstream at angle \(\theta = \sin^{-1}(v_r/v_m)\).
Updated On: Apr 23, 2026
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Show Solution

The Correct Option is D

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