Question

A magnetic dipole is suspended in a region where two uniform magnetic fields are inclined at \(75^\circ\) with each other. In stable equilibrium, if the dipole makes an angle of \(30^\circ\) with the direction of field of \(10\sqrt2\,\text{mT}\), then the value of the second magnetic field is

• A. \(20\sqrt2\,\text{mT}\)
• B. \(10\sqrt2\,\text{mT}\)
• C. \(10\,\text{mT}\)
• D. \(20\,\text{mT}\)

Hint:

For two magnetic fields making an angle \(\theta\), \[ \boxed{ \tan\alpha= \frac{B_2\sin\theta} {B_1+B_2\cos\theta}, } \] where \(\alpha\) is the angle made by the resultant field with \(B_1\). A freely suspended magnetic dipole always aligns along the resultant magnetic field.

Answer 1

The Correct Option is C