Question

The energy of a photon is \(6.6 \times 10^{-19} \, \text{J}\). What is the frequency of the photon?
(Take Planck’s constant \(h = 6.6 \times 10^{-34} \, \text{Js}\))

• A. \(1 \times 10^{15} \, \text{Hz}\)
• B. \(5 \times 10^{14} \, \text{Hz}\)
• C. \(2 \times 10^{15} \, \text{Hz}\)
• D. \(1 \times 10^{14} \, \text{Hz}\)

Hint:

Remember: \(E = h\nu\) is a fundamental relation in quantum physics used to calculate photon frequency from its energy.

Answer 1

The Correct Option is A

Step 1: Apply the energy-frequency relationship The energy of a photon is defined as: \[ E = h u \] Given: - \(E = 6.6 \times 10^{-19} \, \text{J}\) - \(h = 6.6 \times 10^{-34} \, \text{Js}\) Step 2: Solve for frequency \(u\) Rearranging the formula: \[ u = \frac{E}{h} = \frac{6.6 \times 10^{-19}}{6.6 \times 10^{-34}} = 1 \times 10^{15} \, \text{Hz} \] Answer: The photon's frequency is \(1 \times 10^{15} \, \text{Hz}\). This corresponds to option (1).