A line \(L_1\) passes through the points \( (h,k), (1,2) \) and \( (-3,4) \). The points \( (4,3) \) and \( (h,k) \) lie on the line \(L_2\). Given \(L_1 \perp L_2\), then \( (k-h) \) equals to
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For perpendicular lines, the product of slopes is always \( -1 \). Use collinearity first to form one equation, then use perpendicularity to form the second equation.