Question:medium

A hydrocarbon containing C and H has 75% (by weight) of carbon. 32g of this hydrocarbon was completely burnt in air. What is the weight (in kg) of $CO_2$ formed?

Show Hint

{Conservation of Mass (Carbon):} All Carbon in the reactant goes to $CO_2$. Mass of Carbon in 32g Hydrocarbon = $75%$ of 32 = 24g. Moles of Carbon = $24/12 = 2$ moles. Moles of $CO_2$ = 2 moles. Mass = $2 \times 44 = 88$g. This bypasses formula determination!

Updated On: Mar 31, 2026

0.044
0.088
44
88

Show Solution

The Correct Option is B

Solution and Explanation

Was this answer helpful?

0

Top Questions on Stoichiometry and Stoichiometric Calculations

Questions Asked in TS EAMCET exam

If $\omega \neq 1$ is a cube root of unity, then one root among the $7^{th}$ roots of $(1+\omega)$ is

TS EAMCET - 2025
Complex numbers

If $A = \begin{pmatrix} 1 & 2 & 3 \\ 2 & 1 & 1 \\ 1 & 3 & 1 \end{pmatrix}$ and $B = \begin{pmatrix} 2 & 3 & 4 \\ 3 & 2 & 2 \\ 2 & 4 & 2 \end{pmatrix}$, then $\sqrt{|\text{Adj}(AB)|} =$

TS EAMCET - 2025
Matrices and Determinants

If \( p_1, p_2, p_3 \) are the altitudes and \( a=4, b=5, c=6 \) are the sides of a triangle ABC, then \( \frac{1}{p_1^2} + \frac{1}{p_2^2} + \frac{1}{p_3^2} = \)

TS EAMCET - 2025
Geometry

If \(\alpha, \beta, \gamma, \delta, \epsilon\) are the roots of the equation \(x^5 + x^4 - 13x^3 - 13x^2 + 36x + 36 = 0\) and \(\alpha<\beta<\gamma<\delta<\epsilon\) then \( \frac{\epsilon}{\alpha} + \frac{\delta}{\beta} + \frac{1}{\gamma} = \)

TS EAMCET - 2025
Algebra