Question:medium

A hollow charged metal sphere has a radius ' \(r\) '. If the potential difference between its surface and a point at a distance ' \(3r\) ' from the centre is ' \(v\) ', then the electric field intensity at a distance ' \(3r\) ' is

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Outside sphere: Acts like point charge
Updated On: May 8, 2026
  • \(\frac{V}{2r}\)
  • \(\frac{v}{3r}\)
  • \(\frac{v}{6r}\)
  • \(\frac{v}{4r}\)
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The Correct Option is C

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