Question:medium
A group of 200 people are chosen randomly at a conference. Later, it was found that 120 of them like blue pens and 140 like green pens while 70 like both green and blue pens. Determine the number of people thus chosen who do not like neither green nor blue pens?
A group of 200 people are chosen randomly at a conference. Later, it was found that 120 of them like blue pens and 140 like green pens while 70 like both green and blue pens. Determine the number of people thus chosen who do not like neither green nor blue pens?
Show Hint
Use the formula \(n(A \cup B) = n(A) + n(B) - n(A \cap B)\) for such two-set problems.
Updated On: Mar 26, 2026
- 50
- 20
- 30
- 10
- 40
Show Solution
The Correct Option is D
Solution and Explanation
Was this answer helpful?
0
Top Questions on Miscellaneous
- Let \(y=y(x)\) be the solution of the differential equation \[ x\frac{dy}{dx}=y-x^2\cot x,\quad x\in(0,\pi) \] If \(y\!\left(\frac{\pi}{2}\right)=\frac{\pi^2}{2}\), then \[ 6y\!\left(\frac{\pi}{6}\right)-8y\!\left(\frac{\pi}{4}\right) \] is equal to:
- JEE Main - 2026
- Mathematics
- Miscellaneous
- Let \[ f(x)=\int \frac{dx}{2\left(\frac{3}{2}\right)^x+2x\left(\frac12\right)^x} \] such that \(f(0)=-26+24\log_e(2)\). If \(f(1)=a+b\log_e(3)\), where \(a,b\in\mathbb{Z}\), then \(a+b\) is equal to:
- JEE Main - 2026
- Mathematics
- Miscellaneous
- Let \([\,\cdot\,]\) denote the greatest integer function. Then \[ \int_{-\pi/2}^{\pi/2} \frac{12(3+[x])}{3+[\sin x]+[\cos x]}\,dx \] is equal to:
- JEE Main - 2026
- Mathematics
- Miscellaneous
- The sum of all the elements in the range of
\[ f(x)=\operatorname{sgn}(\sin x)+\operatorname{sgn}(\cos x) +\operatorname{sgn}(\tan x)+\operatorname{sgn}(\cot x), \]
where
\[ x\neq \frac{n\pi}{2},\ n\in\mathbb{Z}, \]
and
\[ \operatorname{sgn}(t)= \begin{cases} 1, & t>0 \\ -1, & t<0 \end{cases} \]
is:
- JEE Main - 2026
- Mathematics
- Miscellaneous
- Want to practice more? Try solving extra ecology questions todayView All Questions
