A glass slab of thickness $6.0$ cm is placed on the piece of paper on which an inkdot is marked. By how much distance would an inkdot appear to be raised? The velocity of light in glass is $2\times 10^8\text{ ms}^{-1}$ and that in air is $3\times 10^8\text{ ms}^{-1}$.

Question

A light ray is passing from air (refractive index $ \mu_1 = 1.0 $) into water (refractive index $ \mu_2 = 1.33 $). If the angle of incidence in air is 30°, what is the angle of refraction in water?

Answer 1

Step 1: Apparent Depth:
Apparent depth $=\dfrac{\text{real depth}}\mu=\dfrac6{1.5}=4$ cm.

Step 2: Shift:
Raise $=6-4=2$ cm.

Step 3: Answer:
Option (A).

Final Answer:
Option (A). \[ \boxed{\text{(A) } 2.0\ \text{cm}} \]

A glass slab of thickness \(6.0\) cm is placed on the piece of paper on which an inkdot is marked. By how much distance would an inkdot appear to be raised? The velocity of light in glass is \(2\times 10^8\text{ ms}^{-1}\) and that in air is \(3\times 10^8\text{ ms}^{-1}\).

Show Hint

The Correct Option is A

Solution and Explanation

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