Question

A glass slab (\( \mu = 1.5 \)) of thickness 6 cm is placed over a paper. The shift in the letters printed on the paper will be:

• A. 2 cm
• B. 1 cm
• C. 4 cm
• D. 3 cm

Hint:

The apparent shift due to a glass slab is given by \( \Delta x = t \left( 1 - \frac{1}{\mu} \right) \). Remember, the refractive index \( \mu \) reduces the apparent thickness of the object.

Answer 1

The Correct Option is A

When a glass slab is positioned over an object, the observed displacement is dependent on the slab's thickness and its refractive index. The formula for the apparent shift \( \Delta x \) is: \[ \Delta x = t \left( 1 - \frac{1}{\mu} \right) \] Here: - \( t \) represents the thickness of the slab, - \( \mu \) denotes the refractive index of the material. Given: - \( t = 6 \, \text{cm} \), - \( \mu = 1.5 \). Upon substitution of these values: \[ \Delta x = 6 \left( 1 - \frac{1}{1.5} \right) = 6 \left( 1 - \frac{2}{3} \right) = 6 \times \frac{1}{3} = 2 \, \text{cm} \] Consequently, the apparent shift in the printed letters on the paper is 2 cm.