Question

A Glass Jar contains 1 Red, 3 Green, 2 Blue and 4 Yellow marbles. If a single marble is chosen then Match List I with List II:

List I	List II
(A) Probability of yellow marble	(I) \(\frac{1}{3}\)
(B) Probability of green marble	(II)\(\frac{7}{10}\)
(C) Probability of either green or yellow marble	(III) \(\frac{1}{2}\)
(D) Probability of either red or yellow marble	(IV) \(\frac{4}{10}\)

Choose the correct answer from the options given below

• A. (A)-(II), (B)-(III), (C)-(IV), (D)-(1)
• B. (A)-(1), (B)-(IV), (C)-(II), (D)-(III)
• C. (A) - (IV) B)-(I), (C)-(II), (D)-(III)
• D. (A)-(IV), (B)-(II), (C)-(III), (D)-(1)

Answer 1

The Correct Option is C

Total marbles: \( 1 + 3 + 2 + 4 = 10 \).

• Probability of yellow: \[ P(\text{Yellow}) = \frac{4}{10} = 0.4 = (\text{IV}) \]
• Probability of green: \[ P(\text{Green}) = \frac{3}{10} = 0.3 = (\text{I}) \]
• Probability of green or yellow: \[ P(\text{Green or Yellow}) = \frac{3 + 4}{10} = \frac{7}{10} = 0.7 = (\text{II}) \]
• Probability of red or yellow: \[ P(\text{Red or Yellow}) = \frac{1 + 4}{10} = \frac{5}{10} = 0.5 = (\text{III}) \]

Matches: (C)-(IV), (B)-(I), (C)-(II), (D)-(III).