A full adder is a digital circuit that adds two binary digits and a carry-in. However, in this circuit, \( Z \) is connected to the carry-in input and is set to logic ‘1’. This configuration will cause the circuit to subtract \( Y \) from \( X \).
Here's why:
The XOR gate is used to perform a subtraction operation in digital circuits, where the input \( X \) and \( Y \) are processed with the logic ‘1’ carry-in (i.e., the full adder behaves like a subtractor with the carry-in being ‘1’).
In this case, \( X \) and \( Y \) will be subtracted, producing the desired difference.
Thus, the overall circuit functions as a subtractor when \( Z \) is set to ‘1’. Hence, the correct answer is (B).

In the circuit shown, assuming the threshold voltage of the diode is negligibly small, then the voltage \( V_{AB} \) is correctly represented by:
The value of current \( I \) in the electrical circuit as given below, when the potential at \( A \) is equal to the potential at \( B \), will be _____ A. 
The Boolean expression $\mathrm{Y}=\mathrm{A} \overline{\mathrm{B}} \mathrm{C}+\overline{\mathrm{AC}}$ can be realised with which of the following gate configurations.
A. One 3-input AND gate, 3 NOT gates and one 2-input OR gate, One 2-input AND gate
B. One 3-input AND gate, 1 NOT gate, One 2-input NOR gate and one 2-input OR gate
C. 3-input OR gate, 3 NOT gates and one 2-input AND gate
Choose the correct answer from the options given below: