Question

A frictionless wire AB is fixed on a sphere of radius R. A very small spherical ball rolls on this wire. The time taken by this ball to slip from A to B is: 

• A. \(\dfrac{\sqrt{2gR}}{g\cos\theta}\)
• B. \(\dfrac{2\sqrt{gR}\cos\theta}{g}\)
• C. \(2\sqrt{\dfrac{R}{g}}\)
• D. \( \dfrac{2\sqrt{gR}\cos\theta}{g} \)

Hint:

For motion along a smooth wire: a = gcosθ Use kinematics directly since no friction is involved.

Answer 1

The Correct Option is A