Question

A force of \( 10 \, \text{N} \) acts on a body and moves it through a displacement of \( 5 \, \text{m} \) in the direction of the force. What is the work done by the force?

• A. \( 50 \, \text{J} \)
• B. \( 25 \, \text{J} \)
• C. \( 10 \, \text{J} \)
• D. \( 5 \, \text{J} \)

Hint:

When the force and displacement are in the same direction, the work done is simply the product of the force and the displacement.

Answer 1

The Correct Option is A

A force of \( F = 10 \, \text{N} \) causes a displacement of \( d = 5 \, \text{m} \) in its direction. Step 1: Calculate work done Work done is calculated using the formula: \[ W = F \times d \times \cos \theta \] As force and displacement are in the same direction, \( \theta = 0^\circ \), making \( \cos 0^\circ = 1 \). \[ W = 10 \times 5 \times 1 = 50 \, \text{J} \] Answer: The calculated work done is \( 50 \, \text{J} \).