Question

A flywheel rotating about a fixed axis has a kinetic energy of \(500\) joule, if its angular frequency is \(5\) Hz, then calculate the moment of inertia of the wheel about the axis of rotation. (\(π^2 = 10\))

• A. \(0.6\text{ kg m}^2\)
• B. \(1\text{ kg m}^2\)
• C. \(0.75\text{ kg m}^2\)
• D. \(0.15\text{ kg m}^2\)

Hint:

Use $\omega=2\pi f$ and $K=\frac12I\omega^2$.

Answer 1

The Correct Option is B

Step 1: Solve for $I$ first
$I=\frac{2K}{\omega^2}=\frac{1000}{(10\pi)^2}=\frac{1000}{100\pi^2}=\frac{10}{\pi^2}=1$ kg m$^2$.

Final Answer:
Option (B). \[ \boxed{\text{(B)}} \]