Question:medium
A dishonest seller sells his grocery items using a false weight and thus gains 5% for a kilogram. He uses the weight of approximately ______.
A dishonest seller sells his grocery items using a false weight and thus gains 5% for a kilogram. He uses the weight of approximately ______.
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Set up the gain percent as (1000 - x)/x times 100 equals 5.
Updated On: Jul 16, 2026
- 940.251
- 943.123
- 948.238
- 952.381
Show Solution
The Correct Option is D
Solution and Explanation
Step 1: Treat this as a standard profit percent problem instead.
The seller sells goods worth 1000 grams in price, but physically weighs out only $x$ grams and hands that over as a full "1 kg". So the selling price for $x$ grams worth of cost equals the price of 1000 grams.
Step 2: Write the SP to CP ratio.
$\dfrac{SP}{CP} = \dfrac{1000}{x}$, and since the gain percent is 5, we also know $\dfrac{SP}{CP} = 1 + \dfrac{5}{100} = 1.05$.
Step 3: Equate the two ratios and solve.
$\dfrac{1000}{x} = 1.05$, so $x = \dfrac{1000}{1.05} = 952.381$ grams approximately.
Final Answer:
Both the shortfall method and the SP by CP ratio method agree, the seller uses about 952.381 grams as his false kilogram.
\[ \boxed{952.381} \]
The seller sells goods worth 1000 grams in price, but physically weighs out only $x$ grams and hands that over as a full "1 kg". So the selling price for $x$ grams worth of cost equals the price of 1000 grams.
Step 2: Write the SP to CP ratio.
$\dfrac{SP}{CP} = \dfrac{1000}{x}$, and since the gain percent is 5, we also know $\dfrac{SP}{CP} = 1 + \dfrac{5}{100} = 1.05$.
Step 3: Equate the two ratios and solve.
$\dfrac{1000}{x} = 1.05$, so $x = \dfrac{1000}{1.05} = 952.381$ grams approximately.
Final Answer:
Both the shortfall method and the SP by CP ratio method agree, the seller uses about 952.381 grams as his false kilogram.
\[ \boxed{952.381} \]
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