Question:medium

A disc spinning at the rate \(27.5\ \text{rad s}^{-1}\) is slowed at the rate \(10\ \text{rad s}^{-2}\). The time after which it will come to rest is

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For rotational deceleration, the equation is exactly like linear motion: \[ \omega=\omega_0+\alpha t \]
Updated On: Apr 29, 2026
  • \(2.75\) s
  • \(5.5\) s
  • \(1.25\) s
  • \(3.5\) s
  • \(6.2\) s
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The Correct Option is A

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