Question:medium

A disc of mass \(M\) and radius \(R\) has a concentric hole of radius \(R/2\). Its moment of inertia about an axis passing through its center and perpendicular to its plane is:

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For an annular disc: \[ I=\frac12 M(R_1^2+R_2^2) \] where: \[ R_1=\text{inner radius} \] \[ R_2=\text{outer radius} \] This formula is extremely important for rotational motion problems.
Updated On: May 16, 2026
  • \(\dfrac{15}{32}MR^2\)
  • \(\dfrac{13}{32}MR^2\)
  • \(\dfrac{5}{16}MR^2\)
  • \(\dfrac{3}{8}MR^2\)
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The Correct Option is B

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