Question:medium

A disc of mass $M$ and radius $R$ has a concentric hole of radius $\dfrac{R}{2}$. Its moment of inertia about an axis passing through its center and perpendicular to its plane is:

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For an annular disc: \[ I = \frac{1}{2}M(R_1^2 + R_2^2) \] Always check whether the given mass belongs to the original disc or the remaining annular disc.
Updated On: May 16, 2026
  • $\dfrac{15}{32}MR^2$
  • $\dfrac{13}{32}MR^2$
  • $\dfrac{5}{16}MR^2$
  • $\dfrac{3}{8}MR^2$
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The Correct Option is A

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