Question:medium

A disc is performing pure rolling on a smooth stationary surface with constant angular velocity as shown in the figure. At any instant, for the lower most point of the disc
 

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In pure rolling motion, the velocity at the point of contact is zero, but the acceleration is non-zero and is given by \( \frac{v^2}{R} \).
Updated On: Mar 24, 2026
  • velocity is \( v \), acceleration is zero
  • velocity is zero, acceleration is zero
  • velocity is \( v \), acceleration is \( \frac{v^2}{R} \)
  • velocity is zero, acceleration is \( \frac{v^2}{R} \)
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The Correct Option is D

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