Question

A deuteron of kinetic energy 50keV is describing a circular orbit of radius 0.5m in a plane perpendicular to the magnetic field B. The kinetic energy of the proton that describes a circular orbit of radius 0.5m in the same plane with the same B is:

• A. \(25\,\text{keV}\)
• B. \(50\,\text{keV}\)
• C. \(100\,\text{keV}\)
• D. 200keV

Hint:

For same radius in magnetic field: K ∝ (1)/(m).

Answer 1

The Correct Option is C