With at most \(3\) nodes allowed (S, one stop, E), only single-hop-through routes of the form S-to-hub-to-E are even eligible, so a direct look at each of the three hubs settles it. From S you can reach A or B directly, but not C (nothing points from S into C). Of those two, only A also has a direct link onward to E; B connects onward only to C, not to E, so a route through B can't finish in two steps. Adding a second intermediate stop, such as going through both A and C, would push the route to four nodes total, which the "\(3\) nodes including S and E" limit rules out immediately. That leaves exactly one route that fits every requirement: \(S\to A\to E\), so the number of valid routes is \(\boxed{1}\).