Question

A dealer bought a fixed number of laptops from 3 different companies A, B and C. Among these laptops, \(28\%\) are bought from A, \(32\%\) are bought from B and \(40\%\) are bought from C. \(2.5\%\) of laptops bought from A, \(1.5\%\) bought from B and \(1\%\) bought from C are likely to be defective. If a customer found that the laptop bought by him is defective, then the probability that it was from B is

• A. \(\dfrac{12}{39}\)
• B. \(\dfrac{49}{158}\)
• C. \(\dfrac{17}{78}\)
• D. \(\dfrac{24}{79}\)

Hint:

For questions involving conditional probability after observing an event, use Bayes' theorem: \[ \boxed{ P(A_i|B) = \frac{P(A_i)P(B|A_i)} {\sum P(A_j)P(B|A_j)} } \]

Answer 1

The Correct Option is D