A current element X is connected across an AC source of emf \(V = V_0\ sin\ 2πνt\). It is found that the voltage leads the current in phase by \(\frac{π}{ 2}\) radian. If element X was replaced by element Y, the voltage lags behind the current in phase by \(\frac{π}{ 2}\) radian.
(I) Identify elements X and Y by drawing phasor diagrams.
(II) Obtain the condition of resonance when both elements X and Y are connected in series to the source and obtain expression for resonant frequency. What is the impedance value in this case?
In AC circuits, phasor diagrams illustrate the relationship between voltage and current.

Resonance in a series RLC circuit occurs when inductive reactance (\( X_L \)) equals capacitive reactance (\( X_C \)).
The resonance condition is defined as:
\[ X_L = X_C \Rightarrow \omega L = \frac{1}{\omega C} \]
Solving for \( \omega \) yields:
\[ \omega^2 = \frac{1}{LC} \Rightarrow \omega = \frac{1}{\sqrt{LC}} \]
The resonant frequency \( f \) is calculated as:
\[ f = \frac{\omega}{2\pi} = \frac{1}{2\pi \sqrt{LC}} \]
At resonance, \( X_L = X_C \), resulting in zero net reactance. Consequently, the total impedance \( Z \) becomes purely resistive:
\[ Z = R \]
Resonance in an RLC circuit is achieved when inductive reactance matches capacitive reactance. This condition leads to maximum current and a purely resistive impedance. The resonant frequency is given by:
\[ f = \frac{1}{2\pi \sqrt{LC}} \]

