Question:medium

A current element X is connected across an AC source of emf \(V = V_0\ sin\ 2πνt\). It is found that the voltage leads the current in phase by \(\frac{π}{ 2}\) radian. If element X was replaced by element Y, the voltage lags behind the current in phase by \(\frac{π}{ 2}\) radian. 
(I) Identify elements X and Y by drawing phasor diagrams.
(II) Obtain the condition of resonance when both elements X and Y are connected in series to the source and obtain expression for resonant frequency. What is the impedance value in this case?

Updated On: Jan 13, 2026
Show Solution

Solution and Explanation

Phasor Diagrams, Resonance Condition, and Resonant Frequency

(I) Phasor Diagrams

In AC circuits, phasor diagrams illustrate the relationship between voltage and current.

For Capacitor (X):

  • In a capacitor, voltage leads current by \( \frac{\pi}{2} \). This is due to capacitive reactance, where current leads voltage.
  • The phasor diagram depicts the voltage phasor preceding the current phasor.

For Inductor (Y):

  • In an inductor, voltage lags current by \( \frac{\pi}{2} \). This occurs because inductive reactance opposes changes in current, causing voltage to lead.
  • The phasor diagram shows the voltage phasor trailing the current phasor.

    Phasor Diagrams

(II) Condition of Resonance and Resonant Frequency

Resonance in a series RLC circuit occurs when inductive reactance (\( X_L \)) equals capacitive reactance (\( X_C \)).

Condition for Resonance:

The resonance condition is defined as:

\[ X_L = X_C \Rightarrow \omega L = \frac{1}{\omega C} \]

Solving for \( \omega \) yields:

\[ \omega^2 = \frac{1}{LC} \Rightarrow \omega = \frac{1}{\sqrt{LC}} \]

Resonant Frequency:

The resonant frequency \( f \) is calculated as:

\[ f = \frac{\omega}{2\pi} = \frac{1}{2\pi \sqrt{LC}} \]

Impedance at Resonance:

At resonance, \( X_L = X_C \), resulting in zero net reactance. Consequently, the total impedance \( Z \) becomes purely resistive:

\[ Z = R \]

At Resonance:

  • The impedance \( Z \) equals the circuit's resistance \( R \).
  • Current reaches its maximum value and is in phase with the voltage.

Summary:

Resonance in an RLC circuit is achieved when inductive reactance matches capacitive reactance. This condition leads to maximum current and a purely resistive impedance. The resonant frequency is given by:

\[ f = \frac{1}{2\pi \sqrt{LC}} \]

Was this answer helpful?
1