Question:medium
A cubic curve $y = f(x)$ passes through the points $(1, -7)$ and $(2, 11)$. If $\frac{dy}{dx} = 6x^2 + kx - 5$, where $k$ is a constant, then $f(x) =$}
A cubic curve $y = f(x)$ passes through the points $(1, -7)$ and $(2, 11)$. If $\frac{dy}{dx} = 6x^2 + kx - 5$, where $k$ is a constant, then $f(x) =$}
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Check the options! All options start with $2x^3$ and have $-5x$. Testing point $(1, -7)$ in the options is often faster.
For (B): $2(1) + 3(1) - 5(1) - 7 = -7$. Matches.
For (A): $2 + 6 - 5 - 7 = -4 \neq -7$.
For (B): $2(1) + 3(1) - 5(1) - 7 = -7$. Matches.
For (A): $2 + 6 - 5 - 7 = -4 \neq -7$.
Updated On: Jun 24, 2026
- $2x^3 + 6x^2 - 5x - 7$
- $2x^3 + 3x^2 - 5x - 7$
- $2x^3 + 3x^2 - 5x - 4$
- $2x^3 + 3x^2 - 5x - 5$
Show Solution
The Correct Option is B
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