Question

A coin is placed on a disc rotating with an angular velocity \( \omega \). The co-efficient of friction between the disc and the coin is \( \mu \). The maximum distance of the coin from the centre of the disc up to which it will rotate with the disc is

• A. \( \sqrt{\frac{\mu}{\omega^2}} \)
• B. \( \frac{\mu g}{\omega^2} \)
• C. \( \sqrt{\frac{\mu g}{\omega^2}} \)
• D. \( \frac{\mu g}{\omega} \)

Hint:

For circular motion on a rotating disc, static friction provides the centripetal force until its limiting value is reached.

Answer 1

The Correct Option is B