Given: Number of turns, \( N = 200 \)
Coil area, \( A = 0.01 \, \text{m}^2 \)
Magnetic field change, \( \Delta B = 0.5 \, \text{T} \)
Time for change, \( \Delta t = 0.1 \, \text{s} \)
Step 1: Induced emf Formula Faraday's Law states that the induced emf (\( \varepsilon \)) in a coil is: \[ \varepsilon = -N \frac{\Delta \Phi}{\Delta t} \] where \( \Delta \Phi \) is the change in magnetic flux, calculated as \( \Delta \Phi = B A \).
Step 2: Calculate Induced emf First, find the change in magnetic flux: \[ \Delta \Phi = \Delta B \times A = 0.5 \, \text{T} \times 0.01 \, \text{m}^2 = 0.005 \, \text{T m}^2 \] Now, substitute this into the emf formula: \[ \varepsilon = -200 \times \frac{0.005}{0.1} = -200 \times 0.05 = -10 \, \text{V} \] The magnitude of the induced emf is \( 10 \, \text{V} \).
Answer: The correct answer is option (a): 10 V.