Question:medium

A coil has 200 turns and an area of \( 0.01 \, \text{m}^2 \). If the magnetic field changes from 0 to 0.5 T in 0.1 seconds, what is the induced emf in the coil?

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Remember: Faraday's Law gives the induced emf as \( \varepsilon = -N \frac{\Delta \Phi}{\Delta t} \), where \( \Delta \Phi = B A \) is the change in magnetic flux.
Updated On: Nov 26, 2025
  • 1 V
  • 0.5 V
  • 2 V
  • 5 V
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The Correct Option is A

Solution and Explanation

Given: Number of turns, \( N = 200 \)
Coil area, \( A = 0.01 \, \text{m}^2 \)
Magnetic field change, \( \Delta B = 0.5 \, \text{T} \)
Time for change, \( \Delta t = 0.1 \, \text{s} \)

Step 1: Induced emf Formula Faraday's Law states that the induced emf (\( \varepsilon \)) in a coil is: \[ \varepsilon = -N \frac{\Delta \Phi}{\Delta t} \] where \( \Delta \Phi \) is the change in magnetic flux, calculated as \( \Delta \Phi = B A \).

Step 2: Calculate Induced emf First, find the change in magnetic flux: \[ \Delta \Phi = \Delta B \times A = 0.5 \, \text{T} \times 0.01 \, \text{m}^2 = 0.005 \, \text{T m}^2 \] Now, substitute this into the emf formula: \[ \varepsilon = -200 \times \frac{0.005}{0.1} = -200 \times 0.05 = -10 \, \text{V} \] The magnitude of the induced emf is \( 10 \, \text{V} \).

Answer: The correct answer is option (a): 10 V.

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