Question:medium

A circular coil of radius \(10\,\text{cm}\) is carrying a current. From the centre of the coil, the distance of a point on its axis where \[ \frac{dB}{dx} \] becomes maximum is \[ \left( \frac{dB}{dx} \text{ is the rate of change of magnetic field with distance }x \text{ from the centre of the coil} \right) \]

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For a circular current-carrying coil, \[ \boxed{ B=\frac{\mu_0IR^2}{2(R^2+x^2)^{3/2}}. } \] The magnitude of the field gradient is maximum at \[ \boxed{x=\frac{R}{2}.} \]
Updated On: Jul 18, 2026
  • \(40\,\text{cm}\)
  • \(20\,\text{cm}\)
  • \(10\,\text{cm}\)
  • \(5\,\text{cm}\)
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The Correct Option is D

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