Question:medium
A circular coil carrying current ' I ' has radius ' R ' and magnetic field at the centre is ' B '. At what distance from the centre along the axis of the same coil, the magnetic field will be \( \frac{B}{8} \) ?
A circular coil carrying current ' I ' has radius ' R ' and magnetic field at the centre is ' B '. At what distance from the centre along the axis of the same coil, the magnetic field will be \( \frac{B}{8} \) ?
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- Field on axis decreases as $(R^2 + x^2)^{-3/2}$
- Use ratio with centre value to simplify
Updated On: May 4, 2026
- \( R\sqrt{2} \)
- \( R\sqrt{3} \)
- 2R
- 3R
Show Solution
The Correct Option is A
Solution and Explanation
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