
1. Electric Potential from a Point Charge:
The electric potential \( V \) at a location generated by a point charge \( Q \) is calculated using the formula:
\[ V = \frac{kQ}{r} \]
Where:
2. Work Required to Move a Charge:
The work \( W \) expended to transfer a charge \( q \) between two points within an electric field is determined by:
\[ W = q \Delta V \]
In this equation:
3. Electric Potential at Points A and C:
A charge of \( -6 \, \mu C \) is situated at the center (point B) of the semicircle. Consequently, the electric potential at any point on the semicircle, including points A and C, will be identical. This is because all points on the semicircle are equidistant from the central charge, as they lie on the radius.
Therefore, the electric potential at points A and C is equivalent due to their equal distances from the central charge \( -6 \, \mu C \).
4. Work Done Calculation:
Given that the electric potential at both points A and C is identical, the potential difference \( \Delta V \) between them is zero. Consequently, the work done in moving the charge \( +5 \, \mu C \) from point C to point A is calculated as follows:
\[ W = q \Delta V = 5 \, \mu C \times 0 = 0 \]
5. Final Determination:
A point charge \(q = 1\,\mu\text{C}\) is located at a distance \(2\,\text{cm}\) from one end of a thin insulating wire of length \(10\,\text{cm}\) having a charge \(Q = 24\,\mu\text{C}\), distributed uniformly along its length, as shown in the figure. Force between \(q\) and wire is ________ N. 