Question:medium

A certain reaction rate increases \(1000\) folds in the presence of a catalyst at \(27^\circ\mathrm{C}\). The activation energy of the original pathway is \(98\mathrm{\ kJ/mol}\). What is the activation energy of the new pathway?

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Use Arrhenius equation: \(\ln(k_2/k_1) = (E_{a1} - E_{a2})/RT\).
Updated On: Apr 23, 2026
  • \(80.77\mathrm{\ kJ}\)
  • \(56.38\mathrm{\ kJ}\)
  • \(24.67\mathrm{\ kJ}\)
  • \(90.43\mathrm{\ kJ}\)
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The Correct Option is A

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