Question:easy

A car is moving along a straight line and is brought to a stop within a distance of \(200\) m and in time \(10\) s. The initial speed of the car is

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When a body comes to rest under uniform deceleration, the average velocity is \[ \frac{u+v}{2}. \] Using \[ s=\frac{u+v}{2}\,t \] often provides the quickest solution.
Updated On: Jun 26, 2026
  • \(25\ \text{m s}^{-1}\)
  • \(50\ \text{m s}^{-1}\)
  • \(75\ \text{m s}^{-1}\)
  • \(40\ \text{m s}^{-1}\)
Show Solution

The Correct Option is D

Solution and Explanation

Step 1: Use kinematics — car decelerates uniformly to rest.
Given: distance \( s = 200\text{ m} \), time \( t = 10\text{ s} \), final velocity \( v = 0 \).

Step 2: Apply \( s = \frac{(u+v)}{2}\cdot t \).
\( 200 = \frac{u+0}{2}\times 10 \Rightarrow u = \frac{400}{10} = 40\text{ m/s} \)

\[ \boxed{u = 40\text{ m/s}} \]
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