Question

A bullet comes out of the barrel of gun of length 2 m with a speed 80 m/s. The average acceleration of the bullet is

• A. $1.6~m/s^{2}$
• B. $160~m/s^{2}$
• C. $1600~m/s^{2}$
• D. $16~m/s^{2}$

Hint:

A bullet comes out of the barrel of gun of length 2 m with a speed 80 m/s. The average acceleration of the bullet is

Answer 1

The Correct Option is C

To determine the average acceleration of the bullet as it moves through the barrel of the gun, we use the kinematic equations of motion. Here, the relevant equation is:

• \(v^2 = u^2 + 2as\)

where:

• \(v\) is the final velocity of the bullet, \(80 \, \text{m/s}\).
• \(u\) is the initial velocity of the bullet, \(0 \, \text{m/s}\) (since the bullet starts from rest).
• \(a\) is the average acceleration.
• \(s\) is the length of the barrel, \(2 \, \text{m}\).

Substituting the known values into the equation:

• \((80)^2 = 0^2 + 2 \cdot a \cdot 2\)

This simplifies to:

• \(6400 = 4a\)

Solving for \(a\) gives:

• \(a = \frac{6400}{4} = 1600 \, \text{m/s}^2\)

Thus, the average acceleration of the bullet is \(1600 \, \text{m/s}^2\). This corresponds to the correct option:
Option: $1600~m/s^{2}$.