A boy can throw a stone up to a maximum height of 10 m. The maximum horizontal distance that the boy can throw the same stone will be?

Question

A particle of mass $m$ is projected with a velocity $u$ making an angle of $30^\circ$ with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height $h$ is _____.

Answer 1

For the maximum vertical height $(H)$ of an upwardly projected body, the formula is $H=\frac {u^2}{(2g)}$ which is equation (i). For the same body, with the same initial velocity, the horizontal distance traveled when projected at an angle $(θ)$ is given by $R=\frac {u^2}{g}$, which is equation (ii). Comparing equations (i) and (ii) yields $R=2H$. Given $H=10\ m$, then $R=2×10\ m$, resulting in $R=20\ m$.

Therefore, the correct option is (A): $20\ m$.

A boy can throw a stone up to a maximum height of 10 m. The maximum horizontal distance that the boy can throw the same stone will be?

The Correct Option is A

Solution and Explanation

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