Question

A body of weight 200 N is suspended from a tree branch through a chain of mass 10 kg. The branch pulls the chain by a force equal to (if $g = 10 \, \text{m/s}^2$):

• A. 150 N
• B. 300 N
• C. 200 N
• D. 100 N

Answer 1

The Correct Option is B

The aggregate force exerted on the chain comprises the body's weight and the chain's intrinsic weight.
1. Body weight: \( 200 \, \text{N} \)
2. Chain weight: \( 10 \times 10 = 100 \, \text{N} \)
Consequently, the combined weight is:
\[\text{Total weight} = 200 + 100 = 300 \, \text{N}\]
As the chain-block system is balanced, the tension \( T \) in the chain must counteract the aggregate weight:
\[T = 300 \, \text{N}\]