Question:medium

A body of mass \(M\) is suspended from the lower end of an aeroplane accelerating horizontally. If the rope can withstand a maximum tension \(T\), then the maximum acceleration of the aeroplane is:

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For a body suspended in an accelerating frame: \[ T=M\sqrt{g^2+a^2}. \] This relation is frequently used in JEE problems.
Updated On: Jun 18, 2026
  • \sqrt{\frac{T^2}{M^2}-g^2}
  • \frac{T}{M}-g
  • \frac{T}{M}+g
  • \sqrt{\frac{T^2}{M^2}+g^2}
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The Correct Option is A

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