A body of mass \(2\text{ kg}\) changes its velocity from \((3\hat{i}-4\hat{j})\text{ m/s\) to \((6\hat{j}+2\hat{k})\text{ m/s}\). What is the change in kinetic energy of the body?}
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For vector velocity, first calculate the square of speed using \(v^2=v_x^2+v_y^2+v_z^2\), then use \(K=\frac{1}{2}mv^2\).