Question:medium
A body of mass 2 kg at rest starts to move under the action of an applied horizontal force of 7 N on a table with coefficient of kinetic friction, 0.1. The kinetic energy of the body in 10 seconds is (\(g = 10 \text{ ms}^{-2}\))
A body of mass 2 kg at rest starts to move under the action of an applied horizontal force of 7 N on a table with coefficient of kinetic friction, 0.1. The kinetic energy of the body in 10 seconds is (\(g = 10 \text{ ms}^{-2}\))
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When mass is 2 kg, kinetic energy numerically equals the square of velocity (\(KE = v^2\)) since the \(1/2\) and \(m\) cancel out. This saves calculation steps.
Updated On: Jun 24, 2026
- 1225 J
- 100 J
- 2025 J
- 625 J
- 725 J
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The Correct Option is D
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