Question

A body is thrown vertically upwards from A, the top of a tower, and reaches the ground in time t₁. If it is thrown vertically downwards from A with the same speed, it reaches the ground in time t₂. If it is allowed to fall freely from A, then the time taken to reach the ground is

• A. \( t = \dfrac{t_1 + t_2}{2} \)
• B. \( t = \dfrac{t_1 - t_2}{2} \)
• C. \( t = \sqrt{t_1 t_2} \)
• D. t = √((t₁)/(t₂))

Hint:

For problems involving throws from the same height: • Use equations of motion consistently. • Free-fall time often comes as the geometric mean.

Answer 1

The Correct Option is C