Question:medium

A body cools from a temperature of $60^\circ\mathrm{C}$ to $50^\circ\mathrm{C}$ in 10 minutes and $50^\circ\mathrm{C}$ to $40^\circ\mathrm{C}$ in 15 minutes. The time taken in minutes for the body to cool from $40^\circ\mathrm{C}$ to $30^\circ\mathrm{C}$ is

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When using Newton's Law of Cooling $\frac{dT}{dt} = -K(T_{avg} - T_s)$, always find the surrounding temperature $T_s$ first using the first two conditions.
Updated On: Mar 26, 2026
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The Correct Option is A

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