A body gaining a positive charge indicates the loss of electrons. As electrons possess mass, their removal results in a reduction of the body's mass.
Individual electron properties:
Charge, \( e = 1.6 \times 10^{-19} \, \text{C} \)
Mass, \( m_e = 9.1 \times 10^{-31} \, \text{kg} \)
Net charge acquired:
\( Q = +8.0 \times 10^{-12} \, \text{C} \Rightarrow \) electrons were lost.
Quantity of electrons lost:
\[n = \frac{Q}{e} = \frac{8.0 \times 10^{-12}}{1.6 \times 10^{-19}} = 5 \times 10^7\]Total mass loss:
\[\Delta m = n \times m_e = (5 \times 10^7) \times (9.1 \times 10^{-31}) = 4.55 \times 10^{-23} \, \text{kg}\]Consequently, the body's mass diminishes by \( 4.55 \times 10^{-23} \, \text{kg} \).
Final answer: \({4.55 \times 10^{-23} \, \text{kg decrease}} \)