To solve this problem, we need to understand the behavior of light when it reflects off a mirror that is rotated by a small angle. This involves applying the principles of reflection and geometry. Let's analyze the situation step-by-step:
- The beam of light from the source \( L \) hits the plane mirror normally, meaning the angle of incidence is \( 0^\circ \). It gets reflected back to a spot on the scale above the source.
- When the mirror is rotated through a small angle \( \theta \), the normal to the mirror also rotates by \( \theta \).
- Due to the rotation of the mirror, the incident angle becomes \( \theta \) and by the law of reflection, the reflected angle also becomes \( \theta \).
- The total change in the direction of the reflected beam (from the initial position) is \( 2\theta \). This is because a rotation of the mirror by \( \theta \) causes the already reflected incident angle to shift by an additional \( \theta \), summing up to \( 2\theta \).
- The spot of light on the scale moves by a distance \( y \). Using simple trigonometry, for small angles, the arc length (distance \( y \)) can be approximated using \( y = 2x \tan(2\theta) \), where \( x \) is the distance to the mirror.
- For small angles, \( \tan(2\theta) \approx 2\theta \), hence substituting, we have \( y = 2x \cdot 2\theta = 4x \theta \).
- Solving for \( \theta\), we rearrange the formula: \( \theta = \frac{y}{4x} = \frac{y}{2x} \).
This derivation shows that the angle \( \theta \) can be expressed as:
\(\theta = \frac{y}{2x}\)
Thus, the correct answer is:
\(\theta = \frac{y}{2x}\)
Now, examining the options provided:
- \(\frac{y}{2x}\) - This is the correct option as derived above.
- \(\frac{y}{x}\) - This would imply an incorrect relationship between \( y \) and \( x \).
- \(\frac{x}{2y}\) - This rearrangement does not fit the derived formula either.
- \(\frac{x}{y}\) - Again, not compatible with the relationship established.
Therefore, the correct answer is \(\frac{y}{2x}\).