Question:medium

A ball is thrown vertically upwards with an initial velocity of 20 m/s. Calculate the time it takes for the ball to reach the highest point. (Assume \( g = 9.8 \, \text{m/s}^2 \))

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At the highest point, the velocity of a vertically thrown object becomes zero. The time to reach the highest point is simply the time taken for the velocity to reduce to zero under the influence of gravity.
Updated On: Nov 26, 2025
  • \( 2.04 \, \text{s} \)
  • \( 1.8 \, \text{s} \)
  • \( 3.0 \, \text{s} \)
  • \( 4.0 \, \text{s} \)
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The Correct Option is A

Solution and Explanation

At its apex, the ball's velocity is null. Applying the equation of motion: \[v = u + at\] where: - \( v = 0 \, \text{m/s} \) denotes the velocity at the highest point, - \( u = 20 \, \text{m/s} \) is the initial velocity, - \( a = -g = -9.8 \, \text{m/s}^2 \) represents the downward acceleration due to gravity. Rearranging the formula to determine time \( t \): \[0 = 20 - 9.8 \times t\] \[t = \frac{20}{9.8} = 2.04 \, \text{s}\] Consequently, the time required for the ball to ascend to its peak is \( 2.04 \, \text{s} \).
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