Question:medium

A bag contains 5 red and 4 black balls. Three balls are drawn at random from the bag. The probability that two of them are red and one is black is:

Show Hint

Always simplify combinations first: $^{5}C_2 = 10$ and $^{9}C_3 = 84$. This makes dividing $\frac{40}{84}$ to get $\frac{10}{21}$ straightforward.
Updated On: May 31, 2026
  • $\frac{5}{21}$
  • $\frac{10}{21}$
  • $\frac{5}{14}$
  • $\frac{25}{84}$
Show Solution

The Correct Option is B

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