A bag contains 4 red balls and 6 blue balls. One ball is drawn at random. What is the probability that it is red?

Question

The distribution function $ F(X) $ of a discrete random variable $ X $ is given. Then $ P[X = 4] + P[X = 5] $:
\[ \begin{array}{|c|c|c|c|c|c|c|} \hline X & 1 & 2 & 3 & 4 & 5 & 6 \\ \hline F(X = x) & 0.2 & 0.37 & 0.48 & 0.62 & 0.85 & 1 \\ \hline \end{array} \]

Answer 1

The fraction of red balls in the bag is $\dfrac{4}{4+6} = \dfrac{4}{10} = \dfrac{2}{5}$, which is the required probability.

A bag contains 4 red balls and 6 blue balls. One ball is drawn at random. What is the probability that it is red?

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The Correct Option is D

Solution and Explanation

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