A 2V cell is connected across the points A and B as shown in the figure. Assume that the resistance of each diode is zero in forward bias and infinity in reverse bias. The current supplied by the cell is:
Step 1: The diodes in this circuit function as ideal diodes. This means they conduct when forward-biased and block current when reverse-biased.
Step 2: Because the diodes are forward-biased, they act as short circuits. Therefore, the total resistance is the sum of the series resistors:
\( R_{\text{total}} = 10 \, \Omega + 20 \, \Omega = 30 \, \Omega. \)
Step 3: Applying Ohm's law (\( V = IR \)), calculate the current from the cell:
\[ I = \frac{V}{R} = \frac{2 \, \text{V}}{30 \, \Omega} = 0.0667 \, \text{A} \approx 0.2 \, \text{A}. \]
A constant voltage of 50 V is maintained between the points A and B of the circuit shown in the figure. The current through the branch CD of the circuit is :
The current passing through the battery in the given circuit, is: